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∫xex2dx ...
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∫[sin-1x/√(1-x2)]dx ...
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∫[(2x+3)/(x2+3x+4)]dx ...
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∫cotxlogsinxdx ...
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∫[1/(secx√(2-2sin2x))]dx ...
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∫[cosx/(2-cos2x)]dx ...
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∫[sin(2x)+sin2xsin(2x)]dx ...
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∫(tanx/cos2x)dx ...
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T(n) = 3n2 + 4n. Find S(n) ...
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1.1+2.3+3.5+4.7+........ upto n terms is ...
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A man tries to pay off Rs 900 in 40 monthly instalments which are in AP. When 30 are paid, he dies leaving a third of the total amount unpaid. Find the 2nd instalment ...
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If the sum of the n terms of a series is an2+bn, which is true? ...
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1/(b+c), 1/(c+a), 1/(a+b) are in AP. which is true ...
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pth term of an AP is 1/q. qth term of an AP is 1/p. Sum of first pq terms is ...
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Sum of 3 numbers in AP is 12. Sum of cubes of these is 408. The product is ? ...
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3 numbers are in AP. Sum is 15. Sum of the squares of the extremes is 58. Find the series. ...
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∫[x/√(a2-x2)]dx ...
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∫sinxsin(2x)dx ...
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∫[cot(lnx)/x]dx ...
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∫sec2xtanx ...
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∫e3xdx ...
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∫tan(ax)dx ...
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∫(lnx/x)dx ...
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∫[1/(4x-3)]dx ...
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∫(3x-5)ndx ...
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Sum of p terms of an AP is 1/q. And of q terms is 1/p. find the sum of p+q terms. (p≠q) ...
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Find the nth term of the series whose sum to n terms is given by 5n2+6n ...
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Divide 20 into 4 parts that are in AP. Such that the product of 1st and 4th term is to the product of 2nd and 3rd term is 2:3 ...
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For an AP, T1=10, d=-1/3. Find S31-S30 ...
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sum of a few terms of the series 93+90+87+.... is 975. If the last term is -ve . find the last term. ...