Aaakash sir help..


Helium gas undergoes 2 isochoric and isobaric processes...efficiency of the cycle????

I am not understanding the solution....

3 Answers

481
Anurag Ghosh ·

Sir,as u said yesterday
efficiency=Work done by the gas/heat(input)
How would we find the heat input in this case??

283
Sahil Jain ·

Leave the solution
W= area under pv curve= P0V0
Qab= nCvdt= 3/2PoV0
Qbc= nCpdt= 5/2*2P0V0=50V0
Total Heat supplied = 13/2P0V0

n= workdone / total heat supplied = 2/13

481
Anurag Ghosh ·

yaa...r8...thanks..

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