In an arbitrary scale of temperature, water freezes at 40 and boils at 290. What is the boiling point of a liquid in this scale if it boils at 62 degrees celcius.
What formula is used here?
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2 Answers
1The range of temperature in the arbitrary scale is 40 to 290 i.e. 250 divisions....
In Celsius Scale , no.of divisions = 100.
So,
100 divisions of °C Scale corresponds to 250 divisions of Arbitrary Scale.
1 division of °C Scale → 2510 divisions of Arbitrary Scale.
62 divisions of °C Scale → 62x2510 divisions of Arbitrary Scale = 155 divisions.
As the minimum temperature is 40 in the Arbitrary Scale,
62°C = (155 + 40) = 195... [Ans]
