Σ (Qi + Wi) = 0 ....... coz cyclic..........Get W4
efficiency [12]
An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are Q1=5960J, Q2=-5585 J , Q3=-2980 J and Q4= 3645 J respectively.
The corresponding works involved are W1=2200J, W2=-825J, W3=-1100J and W4 respectively.
FInd the value of
a)W4
b) Efficiency
Σ (Qi + Wi) = 0 ....... coz cyclic..........Get W4
efficiency [12]
yep tapans rite ...........
and efficiencey = W/Qin.............................
w = Σall work
Qin = all positive heat thigis sum.....
Aisa kya...... haaan yaad aaya...........
isilye eff. < 1
kash koi Q liberate na hota to sab machines IDEAL hote