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A uniform tube closed at one contains a mercury pallet 10 cm long. When the tube is raised vertically with the closed end upwards the length of the air column trapped is 20cm. Find the length of the air column trapped when the tube is inverted with the closed end downwards. Atmospheric pressure =75cm of Hg.

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1
Ashish Sharma ·

In 1st case, pressure in the air column = 75 - 10 = 65 cm of Hg

In 2nd case, pressure in the air column = 75 + 10 = 85 cm of Hg

now, applying PV = constant

=> 65 * 20 * A = 85 * L*A
=> L= 15.29 cm

Is is the correct answer ??

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