1This is actually simple,
V2/R is the rate of heat generated.
Let: Water has latent heat of condensation = L per unit mass
Let rate of ice dissolved be "m/second"
Thus, V2/R = mL
m=V2/(RL)
Mass melting per unit time is
V2/(RL)
Am I correct?
If a wire of Resistance 20Ω is covered with ice (at 0°C) and a voltage of 210V is applied across the wire find the rate of melting of ice
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3 Answers
1This is a decent question for calorimetry. You can try to solve.
You have to try to find the maximum rate of melting.
because one can argue about the conductivity of heat and that heat will spread and not be able to melt ice at all... but we are not taking that into consideration.
1Because, no on has solved it yet, i will tell u guys that there is a small thing that i left vague. I hope it is not because of this that.
U have to take a few assumptions! like the latent heat of ice!
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