3SEE SINCE TEMP. DOSNT CHANGE dU =0 ....now Q=W=PdV ......... BUT NOW DA GAS IS IN A CYLINDER...HENCE VOLUME IS A CONSTANT!!!!!!!!!!!!!!!!SO W=0 ........
THEREFORE Q=0!!!!!!!!!!!!!!!!!!!!!(ONLY THEORITICAL!!!!!!)..TELL ME IF IM RONG!!!!!
3Hey iitcoming, i think the answer should be B....
v need to take into account the change in intrnal energy due to change in degrees of freedom...
Ui = N * (5/2RT) (as diatomic has 5 degrees of freedom)
Uf= (2N) * (3/2RT) (as disscoiated gas behaves as monoatmic, having 3 degrees of freedom)
1yes you are right nihit i wonder why the post is pinked
1why iitcommin's post is pinked ...
