Length and breadth of Al same and glass should be same at 00C..
Let it Be pxq
20=p(1+aΔθ) ....
30=q(1+aΔθ) .....
a = 9*10-6
Δθ=400
now let LxB be dimension of Al frame at 400
so L=p(1+bΔθ)
B=q(1+bΔθ)
b=24*10-6
we know value of p and q from above equations..
so LxB can be found...