Well...
Let dl be change in length...
starin in steel is (dls-dl)/l0
strain in Al is (dl-dlAl)/l0
Now 2(dls-dl)/l0YsA=(dl-dlAl)/l0YAlA
dls=l0αsΔθ
dlAl=l0αAlΔθ
solve to get dl+l0
two steel rods and an aluminium rod of equal length l0 and equal cross section are joined rigidly at their ends a sshown in the figure below. all the rods are in a state of zero tension at 00C.
Find the length of the system when the temperature is raised to θ.Coefficient of linear expansion of aluminium and steel are αa and αs respectively. young's modulus of aluminium is Yaand that of steel is Ys.
Well...
Let dl be change in length...
starin in steel is (dls-dl)/l0
strain in Al is (dl-dlAl)/l0
Now 2(dls-dl)/l0YsA=(dl-dlAl)/l0YAlA
dls=l0αsΔθ
dlAl=l0αAlΔθ
solve to get dl+l0