THERMO : MATCH

A. for adiabatic the chang in U = negative of work done.........

in the other 1 dU is same but work done is more as u can see area under graph is more along circle ............. thus A is positive

B. W is evidently negative ,,,,,,,,,,,,,, and temp at B is same as A so dU is negative so B<0
(NEGATIVE)

C. W<0 and since P,V decreases dT<0 so dU<0 and thus Q<0

(NEGATIVE)

SORRY C ko edit kar diya ........... didnt read question properly thought its from A TO D .......

still remains negative though............

only A req. sum analysis others are straight forward..............

see post #2 every thing is there ....telme if u didnt understand.........

But,

Adiabtaic Expansion ==> "-ve Work" doesnt it??

Can u pl. expand a lil on process in (1)

no yaar its just the area under the graph ......... and since its expandin its positive ... pls tellme more specifically wat u didnt understand???