thermodynamics 5

JEE Advanced 2015 Sample Questions › Thermal physics questions › thermodynamics 5

Two monoatomic ideal gas at temperature T1 and T2 are mixed. There is no loss of energy. If the masses of the molecules are m₁ and m₂ and the number of their molecules are n₁ and n₂ resp.

The temperature of the mixture will be

a. T₁+ T₂n₁+ n₂

b. T₁n₁ +T₂n₂

c. n₂T₁+ n₁T₂n₁+ n₂

d.n₁T₁+ n₂T₂n₁+ n₂

#Physics #Thermal physics

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Swarna Kamal Dhyawala ·2013-05-07 22:26:23

the answer must be (D)

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Abhas Agarwal can u give the details
Upvote·0· Reply ·2013-05-08 00:03:26
Shourjya Chakraborty i think the answer is a
Upvote·0· Reply ·2013-09-10 06:33:31
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Swarna Kamal Dhyawala ·2013-05-08 00:16:18

n₁c(T₁) + n₂c(T₂) = (n1 + n2)cT_final
T_final = n₁T₁+n₂T₂n₁+n₂

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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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thermodynamics 5

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