@dwijaraj...
ln 6ln 3 is not ln 2. :P
It's value is 1.6309.
And the lines are not straight...they are curves...you cannot find the slope like you do for a straight line.
ln 6ln 3 ?
Adiabatic exponent=slope of adiabatic curve/slope of isothermal curve
from the graph....
adiabatic exponent=5/4
@dwijaraj...
ln 6ln 3 is not ln 2. :P
It's value is 1.6309.
And the lines are not straight...they are curves...you cannot find the slope like you do for a straight line.