1.heat(W.D). given in teh 1st process is twice...the heat in 2nd...
as chande in temp..is same....ca>cb
2.its an adiabatic process....heat transferd is zero
1-(C) 2-(D) 3-answer not given in the book
Please provide an explanation.
1.heat(W.D). given in teh 1st process is twice...the heat in 2nd...
as chande in temp..is same....ca>cb
2.its an adiabatic process....heat transferd is zero
yes workdone is zero as is independent of path followed more over change in volume is zero.
it is area under the graph as we know
how will any1 justify that.....work done is the area under the PV curve.....which if we take in this case would account for non zero work.....and if we point out that total change in v=0 therefore workdone is 0..........
pleasse solve this paradox!!!!