Another doubt(inverse trigo)

S=Î£_n=1âˆžtan^-11/(2ⁿ+2^1-n) (n ---1 to infinity) Find S. ANS.Î /4

2 Answers

1357

Manish Shankar ·2010-05-21 05:29:50

tan^-112ⁿ+2^1-n=tan^-12-12ⁿ+2^1-n=tan^-12^1-n-2^-n1+2^1-n2^-n=tan^-12ⁿ-tan^-12^n-1=tan^-12ⁿ-tan^-12^n-1

Thanks a lot ,I had been getting stuck in such type of problems.

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