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Evaluate
3(\sin x- \cos x)^4 + 6(\sin x + \cos x)^2+ 4 \sin^6x+4 \cos^6x
IIT JEE 1975
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UP 0 DOWN 0 0 7
7 Answers
virang1 Jhaveri
·2009-03-21 09:31:17
3(sin2x + cos2x -2 cosxsinx)2 + 6(sin2x +cox2x + 2cosxsinx)+4 sin6+4cos6x
= 3(1-2cosxsinx)2+6(1+2cosxsinsx) + 4(sin6x + cos6x)
= 3(1 + 4 cos2xsin2x -4sinxcosx) +6 + 12cosxsinx + 4(sin6x + cos6x)
= 3 + 12 cos2xsin2x - 12sinxcosx + 6 + + 12cosxsinx +4(sin6x + cos6x)
= 9 +12cos2sin2x + 4(sin6x + cos6x)
(sin2x +cos2x)3 = sin6x + cos6x + 3cos2xsin2x(sin2x + cos2x)
9 +12cos2sin2x + 4 - 12cos2sin2x
= 13
Which is the final answer
tapanmast Vora
·2009-03-21 09:54:34
tum logo ne galat kiya hai........
rite METHOD :
LET sinx = 1
==> cosx = 0;
so 3+6+4 = 13 NOW ITS CRRCT [4] [4]