find

find tan10.tan70.tan30

3 Answers

1057
Ketan Chandak ·

then it's 1/3.

229
Dwijaraj Paul Chowdhury ·

tan10tan70

=(2sin10sin70)/(2cos10cos70)
=(cos60-cos80)/(cos60+cos80)
=((1/2)-cos80)/((1/2)+cos80)
=(1-2cos 80)/(1+2cos 80)

therefore multiply tan30 with the expression above
and then i hope u'll be able to solve because i can't :-P

1708
man111 singh ·

\hspace{-16}$May be the question is....\\\\\\ Calculate value of $\bf{\tan(10^0).\tan(30^0).\tan(50^0).\tan(70^0)=}$

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