1take x0 = Cos(θ)
and try to solve it . u get a pattern like this,
x1 = Cos(θ/2)
x2 = Cos(θ/22)....and so on
...
xn = Cos(θ/2n)
now u get a value of
x1.x2.x3......xn = Cos(θ/2).Cos(θ/22)........Cos(θ/2n)
now multiply and divide by Sin(θ/2n)
on solving u get,
x1.x2.x3......xn = (1/2)nSin(θ)/Sin(θ/2n)
uget the value of ,
y = (√1-x02)/x1.x2.x3......xn = 2n.Sin(θ/2n)
on taking limt as n→∞
we get
y = θ
now Cos (y) = Cos (θ)
= x0
so final answer will be x0
