hurdle

was solving a ques..and found this in b/w....and cant solve this step...

for x=-1/2
find value of a^2 if a =cos tan-1 sin cot -1 x

6 Answers

1
Arshad ~Died~ ·

a^2=5/9
is it??

24
eureka123 ·

soln plzz

no hints....plz full soln...i know it wont be longer than 3-4 lines...or even shorter than that

1
Arshad ~Died~ ·

but tell me if 5/9 is correct???

24
eureka123 ·

correct dude

1
Arshad ~Died~ ·

a=cos tan-1 sin cot -1 x
a=cos tan-1 sin sin -1(1/√(1+x2))
a=cos tan -1(1/√(1+x2))
a=cos cos -1 (1/√(1+(1/1+x2))
so
a=√((1+x2)/(2+x2))
now put x=-1/2
and get the ans

24
eureka123 ·

kk ...
thx...
there was some goof up on my side..[3][3]

Your Answer

Close [X]