IIT JEE Past Question Trigonometry 3

Given an isosceles triangle whose one angle is 120 degree and radius of its incircle is √3. Then the area of the triangle in square units is:

6 Answers

11
Subash ·

8√3

62
Lokesh Verma ·

how?

106
Asish Mahapatra ·

area = 12 + 7√3 ?

62
Lokesh Verma ·

yes asish :)

106
Asish Mahapatra ·

s = (2a+√3a)/2
area = 1/2*a/2*√3a = √3a2/4

So, r= area/s = √3a2/4/(2a+√3a)/2 = √3

Solving we get a=2+√3
so area = √3a2/4 = 12+7√3

62
Lokesh Verma ·

good work :)

Your Answer

Close [X]