inverse sum....

\hspace{-16}\bf{\lim_{n\rightarrow \infty}\frac{1}{n}\tan\left\{\sum_{k=1}^{4n+1}\tan^{-1}\left(1+\frac{2}{k.(k+1)}\right)\right\}=}

2 Answers

262

Aditya Bhutra ·2012-05-03 23:13:18

i am getting Ï€

ans:4?

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