somebody plz try this one out ... ..
If a,b,c are in H.P..
prove that :
sin2A2,sin2B2 and sin2C2 ARE ALSO IN h.p.
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2 Answers
Manish Shankar
·2014-01-30 04:45:10
1/a, 1/b, 1/c are in AP
=>s/a, s/b, s/c are in AP
=>s/a - 1, s/b - 1, s/c - 1 are in AP
=>(s-a)/a, (s-b)/b, (s-c)/c are in AP
=>(s-a)/aΔ2, (s-b)/bΔ2, (s-c)/cΔ2 are in AP
=>(s-a)/(as(s-a)(s-b)(s-c)), (s-b)/(bs(s-a)(s-b)(s-c)), (s-c)/(cs(s-a)(s-b)(s-c)) are in AP
=>1/(a(s-b)(s-c)), 1/(b(s-a)(s-c)), 1/(c(s-a)(s-b)) are in AP
=>bc/((s-b)(s-c)), ac/((s-a)(s-c)), ab/((s-a)(s-b)) are in AP
=>1/sin2(A/2), 1/sin2(B/2), 1/sin2(C/2) are in AP
- Himanshu Giria thank u sir
Upvote·0· Reply ·2014-02-01 02:29:00