well i am getting [8sinA/2sinB/2sinC/2] ....
Prove
\frac{sin 2A+sin 2B+ sin 2C}{Cos A + Cos B + Cos C-1}=8cos\frac{A}{2}cos\frac{B}{2}cos\frac{C}{2}
This is from IIT JEE 1977
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Prove
\frac{sin 2A+sin 2B+ sin 2C}{Cos A + Cos B + Cos C-1}=8cos\frac{A}{2}cos\frac{B}{2}cos\frac{C}{2}
This is from IIT JEE 1977