given equals
√32sinx + 12cosx = 2
→ cos 30°sinx + sin30°cosx = 2
→ sin ( x+30°) = 2
which is not possible for any value of x
since
-1 ≤ sinx ≤ 1
so no solution
The equation √3 sin x + cos x = 4 has
(A) only one solution (B) two solutions (C) infinitely many solutions (D) no solution
given equals
√32sinx + 12cosx = 2
→ cos 30°sinx + sin30°cosx = 2
→ sin ( x+30°) = 2
which is not possible for any value of x
since
-1 ≤ sinx ≤ 1
so no solution