Q1 In a triangle ABC r1= 2r2= 3r3. Find a:b .
Q2 In an isoceless triangle ABC one of the angle is 120° and radius of incircle is √3.What is the area of the triangle?
plz post the whole solution as im getting wrong answer in both questions
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5 Answers
62Δs-a=2Δs-b=3Δs-c
s-a:(s-b)/2:(s-c)/3=k
s-a=k
s-b=2k
s-c=3k
s=6k
a=5k
b=4k
c=3k
12)sides be a,a,b
area=(1/2)(a)(asin120)=√3/4 a2
a/sin30=b/sin120
s=a+(b/2)
and (raduis of incircle)=area/s
use them...get the ans
1) r1=s.tan(A/2)
r2=s.tan(B/2)
r3=s.tan(C/2)
tan(A/2) :tan(B/2):tan(C/2)=6:3:2
tanA/2=6k
tanB/2=3k
tanC/2=2k
now in triangle ABC
wer A+B+C=180
tanA/2 .tanB/2 +tanB/2 .tanC/2+tanC/2 .tanA/2=1
1CHE SIR
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