Solve.......

JEE Advanced Tutorials › Trignometry questions › Solve.......

Solve.
1.
log_{((9x-x²-14)/7)}(sin3x-sinx)=log_{((9x-x²-14)/7)}cos2x

2.
2cos²(pi4^x)-sin(pi4^x+1)+sin(pi4^x+1/2)-2cos(pi4^x+1/2)=0

#Mathematics #Trignometry

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7 Answers

1

skygirl ·2008-10-23 20:05:30

q1.) is the ans x=5Ï€/6 and x=13Ï€/6 ???

q2.) is the question corect??

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33

Abhishek Priyam ·2008-10-25 20:46:32

Q.1 absolutly correct...

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33

Abhishek Priyam ·2008-10-25 20:47:16

Try taking pi4^x as y....

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33

Abhishek Priyam ·2008-10-25 20:49:18

the eqn becomes....

2cos²(y)-sin(4y)+sin(2y)-2cos(2y)=0

where y=pi4^x

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1

skygirl ·2008-10-25 20:49:39

ya ya tried dat way only but may b i have copied sumthing wrong

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1

skygirl ·2008-10-25 20:50:52

chhodo.........i will let u know later... now pc on ups... :(

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Abhishek Priyam ·2008-10-25 20:51:20

Ok leave it it involves only calculation as 4y is involved so a lot of calculation.....

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