Solve eqn

Solve:

(cosx)sin2x - (3/2)sinx + 1/2 = 1

5 Answers

39
Pritish Chakraborty ·

This is only possible if the power of cosx is zero...so you get a quadratic in sinx as
sin²x - 3/2 sinx + 1/2 = 0

=> 2sin²x - 3sinx + 1 = 0

Solve the quadratic and find values of sin(x), then you can find values of x. They will be your answer.

30
Ashish Kothari ·

and what if we take the value of cosx as 1?

39
Pritish Chakraborty ·

Yes those are possible values also. Was about to edit my earlier post...for all those values of x which give cosx = 1, sinx is zero and we are left with 1/2 in the power, which in any case leaves 1.

30
Ashish Kothari ·

In the answer, they've not mentioned x = 2n(pi) :(

62
Lokesh Verma ·

ashish the answer is wrong..

Not just that dont miss out the solutions like

base = -1

power is an even integer..

That is something that is most often missed... . (May not be in this question though)

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