This is only possible if the power of cosx is zero...so you get a quadratic in sinx as
sin²x - 3/2 sinx + 1/2 = 0
=> 2sin²x - 3sinx + 1 = 0
Solve the quadratic and find values of sin(x), then you can find values of x. They will be your answer.
This is only possible if the power of cosx is zero...so you get a quadratic in sinx as
sin²x - 3/2 sinx + 1/2 = 0
=> 2sin²x - 3sinx + 1 = 0
Solve the quadratic and find values of sin(x), then you can find values of x. They will be your answer.
Yes those are possible values also. Was about to edit my earlier post...for all those values of x which give cosx = 1, sinx is zero and we are left with 1/2 in the power, which in any case leaves 1.
ashish the answer is wrong..
Not just that dont miss out the solutions like
base = -1
power is an even integer..
That is something that is most often missed... . (May not be in this question though)