I tried by this method
sinB/2 =√(s-c)(s-a)/ca
Therefore, ac=12
Also,
a=s-3
c=s-2
Therefore,a-c=-1
So a=3,c=4
Is this approach fine ?
In right angled triangle ABC,right angled at B,s-a=3 and s-c=2.
Find values of a and c
a=s-3
c=s-2
2s=a+b+c
b=2s-a-b=(s-a)+(s-b)=2+3=5
now i am sure you can solve the rest :)
I tried by this method
sinB/2 =√(s-c)(s-a)/ca
Therefore, ac=12
Also,
a=s-3
c=s-2
Therefore,a-c=-1
So a=3,c=4
Is this approach fine ?