Triangle

In right angled triangle ABC,right angled at B,s-a=3 and s-c=2.
Find values of a and c

3 Answers

62
Lokesh Verma ·

a=s-3
c=s-2

2s=a+b+c
b=2s-a-b=(s-a)+(s-b)=2+3=5

now i am sure you can solve the rest :)

1
champ ·

I tried by this method
sinB/2 =√(s-c)(s-a)/ca
Therefore, ac=12

Also,
a=s-3
c=s-2
Therefore,a-c=-1

So a=3,c=4
Is this approach fine ?

62
Lokesh Verma ·

yup.. i dont see a reason why not :)

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