If 3pi/4<A<pi then √2cotA+cosec2A is equal to ???
is it
(-∞,0)?
z=2cotA+cosec2A=2cotA+1+cot2A=(1+cotA)2
√z=√(1+cotA)2=|1+cotA|
for the given domain
it is -1-cotA
-1-cotA
manish bhaiya can u xplain last step
|1+cotA|=1+cotA when 1+cotA>0=-(1+cotA) when 1+cotA<0
in the given domain cotA<-1 so 1+cotA<0
hence the answer
and y does 1+ cotA come under modulus after taking square root??
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