manish bhaiya can u xplain last step
6 Answers
Manish Shankar
·2009-04-19 03:18:08
z=2cotA+cosec2A=2cotA+1+cot2A=(1+cotA)2
√z=√(1+cotA)2=|1+cotA|
for the given domain
it is -1-cotA
Manish Shankar
·2009-04-19 03:31:50
|1+cotA|=1+cotA when 1+cotA>0
=-(1+cotA) when 1+cotA<0
in the given domain cotA<-1 so 1+cotA<0
hence the answer