trigno rulz

tan@=t

nw
u get a quadratic in terms of t

t^2(b^2-a^2)+2act+b^2-c^2=0

tan α+tan β=-2ac/(b^2-a^2)

tan α*tan β =b^2-c^2/(b^2-a^2)

nw u can find tan(α+β) =tanα+tanβ/(1-tanαtanβ)

nw
u can easily find cos(α+β) ...........also

if no then do knck

tan(α+β)=2ac/a^2-c^2

cos(α+β)==a^2-b^2/a^2+b^2

its corrct???????

cos(α+β)==a^2-b^2/a^2+b^2

its corrct???????

nope dharun
check ur answer again

same ans i am getting

what's the ans??????