Prodipta Bose
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Prodipta Bose
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Equivalent Resistance
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5
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#Physics
#Electricity and magnetism
commented
2013-07-10 22:42:06
Application of Derivatives
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10
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#Mathematics
#Calculus
commented
2013-07-10 07:01:27
Functions(exam problem)
Let f:R-->R be a continuous function such that f(x)-2f( x/2 )+f( x/4 ) = x2. f(3) is equal to (A) f(0) (B) 4+f(0) (C) 9+f(0) (D) 16+f(0). The equation f(x)-x-f(0) = 0 has exactly (A) No solution (B) One solution (C) Two so
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3
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#Mathematics
#Calculus
commented
2013-06-30 08:16:45
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