Here are the Questions i could remember ..... Q.1. What should be the values of x and y such that x2 + y2 is minimum and (x + 5)2 + (y – 12)2 = 142 ?? I got the answer as (x, y) = ( 5/13, -12/13 ) and min value as 1 Q.2. so ...
Evaluate the following integral: \int_{-100}^{-10}\left(\dfrac{x^2-x}{x^3-3x+1}\right)^2\mathrm dx+\int_{\frac{1}{101}}^{\frac{1}{11}}\left(\dfrac{x^2-x}{x^3-3x+1}\right)^2\mathrm dx + \int_{\frac{101}{100}}^{\frac{11}{10}}\l ...
