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Find the following limit for \alpha >1 : \lim_{n\to \infty} n\left(\dfrac{1^\alpha + 2^\alpha + \ldots + n^\alpha}{n^{\alpha+1}}-\dfrac{1}{\alpha +1}\right) Here n is a natural number. ...
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Today I was just watching the big bang on discovery science. Somewhere deep inside, the motivation to study comes. I'll go study some 6 hours now. But the thing is that mostly till the next 4-5 days I'll never open any books. ...
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1.Three particles are situated at 3 vertices of a triangle ABC of side a.Each particle moves with a speed v such that A moves towards B, B towards C and C towards A.Find the trajectory of the the particles. ...
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Find the following limit for \alpha >1 : \lim_{n\to \infty} n\left(\dfrac{1^\alpha + 2^\alpha + \ldots + n^\alpha}{n^{\alpha+1}}-\dfrac{1}{\alpha +1}\right) Here n is a natural number. ...
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Let {D1,D2.......,Dn}be the set of all third order determinants that can be formed with the distinct non-zero real numbers a1,a2....,an,then (A) \sum_{i=1}^{}{n} Di=1 (B) \sum_{i=1}^{}{n} Di=0 (C)Di=Dj for all i,j (D) none. A ...
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1.Three particles are situated at 3 vertices of a triangle ABC of side a.Each particle moves with a speed v such that A moves towards B, B towards C and C towards A.Find the trajectory of the the particles. ...
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1.Three particles are situated at 3 vertices of a triangle ABC of side a.Each particle moves with a speed v such that A moves towards B, B towards C and C towards A.Find the trajectory of the the particles. ...
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1.Three particles are situated at 3 vertices of a triangle ABC of side a.Each particle moves with a speed v such that A moves towards B, B towards C and C towards A.Find the trajectory of the the particles. ...
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find the no. of factors ( excluding 1 and the expression itself ) of the product of a^7 b^4 c^3 d e f where a b c d e f r all prime nos..?? plzzz provide the full soln.... ...
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find the no. of factors ( excluding 1 and the expression itself ) of the product of a^7 b^4 c^3 d e f where a b c d e f r all prime nos..?? plzzz provide the full soln.... ...
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1.Three particles are situated at 3 vertices of a triangle ABC of side a.Each particle moves with a speed v such that A moves towards B, B towards C and C towards A.Find the trajectory of the the particles. ...
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Today I was just watching the big bang on discovery science. Somewhere deep inside, the motivation to study comes. I'll go study some 6 hours now. But the thing is that mostly till the next 4-5 days I'll never open any books. ...
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Evaluate \int_{-1}^1\dfrac{\ln(13-6x)}{\sqrt{1-x^2}}\ \mathrm dx ...
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Evaluate \int_{-1}^1\dfrac{\ln(13-6x)}{\sqrt{1-x^2}}\ \mathrm dx ...
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Evaluate \int_{-1}^1\dfrac{\ln(13-6x)}{\sqrt{1-x^2}}\ \mathrm dx ...
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Evaluate \int_{-1}^1\dfrac{\ln(13-6x)}{\sqrt{1-x^2}}\ \mathrm dx ...
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Evaluate \int_{-1}^1\dfrac{\ln(13-6x)}{\sqrt{1-x^2}}\ \mathrm dx ...
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Evaluate \int_{-1}^1\dfrac{\ln(13-6x)}{\sqrt{1-x^2}}\ \mathrm dx ...
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A body starts sliding (from rest) without friction down a hill of height h. In the beginning the body has potential energy and no kinetic energy; at the end the body has only kinetic energy. It follows from energy conservatio ...
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Today I was just watching the big bang on discovery science. Somewhere deep inside, the motivation to study comes. I'll go study some 6 hours now. But the thing is that mostly till the next 4-5 days I'll never open any books. ...
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find : \frac{29\int_{0}^{1}{\left(1-x^4 \right)^{7}}\mathrm{dx}}{4\int_{0}^{1}{\left(1-x^4 \right)^{6}}\mathrm{dx}} ...
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find : \frac{29\int_{0}^{1}{\left(1-x^4 \right)^{7}}\mathrm{dx}}{4\int_{0}^{1}{\left(1-x^4 \right)^{6}}\mathrm{dx}} ...
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find : \frac{29\int_{0}^{1}{\left(1-x^4 \right)^{7}}\mathrm{dx}}{4\int_{0}^{1}{\left(1-x^4 \right)^{6}}\mathrm{dx}} ...
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find : \frac{29\int_{0}^{1}{\left(1-x^4 \right)^{7}}\mathrm{dx}}{4\int_{0}^{1}{\left(1-x^4 \right)^{6}}\mathrm{dx}} ...
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Why does the characteristic spectrum(they occupy the peaks) have more relative intensity than Continous spectrum?Secondly why does Kalpha occupy a higher peak than Kbeta whereas the energy gap in the latter case is more? ...
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if α, β, γ are connected by the relation 2 tan2α tan2β tan2γ + tan2α tan2β + tan2β tan2γ +tan2γ tan2α =1, then the value of cos2α +cos2β +cos2γ is ________ answer: 1 ...
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\lim_{x\rightarrow \infty}\left(\frac{(1+x)^x}{x^x\times e} \right)^x Source:AOPS ...
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if α, β, γ are connected by the relation 2 tan2α tan2β tan2γ + tan2α tan2β + tan2β tan2γ +tan2γ tan2α =1, then the value of cos2α +cos2β +cos2γ is ________ answer: 1 ...
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TOTAL 2 PROBLEMS *Image* It Came in IITJEE 1999 How To Solve This One ?? PLease solve it in DETAIL Stating HOW you got this ! *Image* Answer in "nCr" or Factorial Form !! ...
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TOTAL 2 PROBLEMS *Image* It Came in IITJEE 1999 How To Solve This One ?? PLease solve it in DETAIL Stating HOW you got this ! *Image* Answer in "nCr" or Factorial Form !! ...