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Kvpy results came. See http://www.kvpy.org.in/main/2011-aptitudetest-results.htm . I didnt qualify. Messed up bio big time :'( . How many of u qualified? ...
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1) Find the range of sin2x + sinx - 1/sin2x - sinx + 2 2) Find range of cosx(sinx + \sqrt{sin^{2}x+sin^{2}\alpha }) ...
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1) Find the set of values of a for which the function f(x)=x3+(a+2)x2+3ax+5 where f: R→R is one-one. 2) Find the condition for f(x)=ax3+bx2+cx+dsinx to be always one-one. ...
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Find the sum of [x]+[x+ 1/n ]+[x+ 2/n ]+......+[x+ n-1/n ] if 'x' is real and 'n' is natural. [.] represents the greatest integer function. ...
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If 2f(sinx)+f(cosx) = x for all real x, find the domain and range. ...
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1) Find all natural n's for which n4 + 2n3 + 2n2 + 2n + 1 is a perfect square. 2) If [a] is the grestest integer not exceeding a and a = 2 + √3 then the value of an + a-n + [an] for any positive integer n is 3) Find the num ...
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If the length of the equal sides of an isoceles triangle is 2011, find the length of the third side such that its area is maximum. ...
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1) If a,b,c,d > 1 P.T. 8(abcd+1) > (a+1)(b+1)(c+1)(d+1) 2) If a,b,c ≥ 0 and a+b+c =1 Find the max. value of \sqrt[ 3 ]{a+b} + \sqrt[ 3 ]{b+c} + \sqrt[ 3 ]{a+c} 3) For a,b,c > 0 Prove that x2 + y2/x+y + z2 + y2/z+y ...
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1) Find 1+2008 1+2009 1+2010 1+2011*2013 2) Find the +ve integers (x,y) which satisfies x2+y2+2xy-2008x-2008y-2009=0 3) an+1 = an + an-1 for n≥2 . a2 = -1 and a10 = 29. Find a1. 4) Find sum of the digits of the number 10002 ...
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*Image* There are six circles of equal radius and are arranged as an equilateral triangle. Find the radius of the circle. ...
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1) A sequence of real number xn is defined as follows... x0 , x1 are arbitary +ve real numbers and xn+2 = 1+xn+1 /xn ,n = 0,1,2,........ Then x2011 is a) 1 b) x0 c) x1 d) x2 2)The eq. log2x 2/x (log2x)2 + (log2x)4 = 1 has a) ...
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1) If f(x) = x2 - x3 find f -1(x) 2) The remainder when the polynomial x+x3+x9+x27+x81+x243 is divided by x2 -1 3) If | x | + x + y =10 x + | y | - y =12 find x + y ...
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Find least no. of digits in x , When f(f(f(f(x)))) = 1 whre f(x) is the sum of the digits in x x > f(x) f(x) > f(f(x)) f(f(x)) > f(f(f(x))) > 1 ...
