Unanswered Calculus Questions

if f(x) = tan2[pi x/(n2-5n+8)] + cot [(n+m)pi x] (n ε N , m ε Q) is a periodic function with '2a' as its fundamental period then find the set of values of 'm' ? ...

BT vs FIITJEE (keeping following in mind) 1.in terms of no of students taking 2.whose percentile is almost equivalent to iit jee(imp) 3.whose que r closely related to iit pleaseeeeeeeeeee give ur votes am in need of it ...

If \alpha =e^{2i\pi/11 } and f(x)=5+\sum_{K=1}^{60}{A_K{x^{K}}} then find value of 100\sum_{r=0}^{10}{f(\alpha ^{r}x}) ...

prove that sinx+2x≥[3x(1+x)]/∩ for xε(0,Π/2) ...

g(x) = ∫ cos4t dt , then g(x+π ) = ? { lower limit =0 upper limit= x} a. g(x) + g(π) b. g(x) - g(π) c.g(x) *g(π) d. g(x)/g(π) ...

g(x) = ∫ cos4t dt , then g(x+π ) = ? { lower limit =0 upper limit= x} a. g(x) + g(π) b. g(x) - g(π) c.g(x) *g(π) d. g(x)/g(π) ...

g(x) = ∫ cos4t dt , then g(x+π ) = ? { lower limit =0 upper limit= x} a. g(x) + g(π) b. g(x) - g(π) c.g(x) *g(π) d. g(x)/g(π) ...

*Image* =? Edit:- denom is 1+sin2√θ ...

*Image* ...

ysin2xdx=dy(1-k(y)^(1/2)cosx) here k is a known constant. ...

For some g,let f(x)=x(x+3)eg(x) be a continuous function. If there exists only one point x=d such that f'(d)=0,then find interval in which d lies. ...

One problem that has been troubling me for ages now.. anyone who can try and solve? ∫(tan x)1/6 dx ...

(y+ y3/3 + x2/2 ) dx + ( x+xy2/4 )dy = 0 solve the above differential equation ...

let f(x) be such that f(xy)=f(x)f(y)....if f(x) is continuos at x=1,show dat f(x) iscontinuous at all x ≠0 ...

Prove 2<e<3 ... ...

FIND THE VALUE OF THE LIMIT AND SAY THE PROCEDURE lim n→∞ 1/2 tan(x/2)+1/22 tan(x/22)+1/23 tan(x/23).........+1/2n tan(x/2n) ...

sir please give steps on calculating the period of a function, ...

1) ∫(tan(pi/4-∂))/sin∂cos∂√(1+tan∂+cot∂) d∂ = -2tan-1√f(∂) + c. Then Minimum value of f(∂) is Opts - 4, 2, 6, 3 2) f(x) and g(x) are two real valued functions. Find the no. of solutions of equation ∫f( ...

sry question got posted twice ...vry sorry for dat , nishant sir remove dis post , btw da question is here http://targetiit.com/iit-jee-forum/posts/functionssss-13844.html [1] ...

sorry deleted the integral ...

* GOT THE ANSWR ** ...

x \int \frac{\sqrt{2sin ( x ^ 2-1 ) - sin 2( x^2 -1 )}}{ \sqrt{2sin ( x^2 -1)+ sin2 ( x^2 -1 )} }where x^2 -1 \neq n\pi ans is log \mid \left( sec \frac{ x^2 -1 }{2} \right) \mid + c for practice ...

draw graph of esin x ...

draw the graph of eesin x ...

Tangents at a point P1 (other than(0,0) on the curve y=x3 meets the curve again at P2. The tangents at P2 meets the curve at P3 and so on. Show that the abscissae of P1,P2, P3,.....Pn form a G.P. Also find the ratio of area o ...

IF ∫(sin 3θ + sin θ)esin θ cos θ dθ = (Asin 3θ + Bcos 2θ + Csin θ + D cos θ + E)esin θ + c find A, B , C , D , E ANS---> -4 , -12 , -20 , 0 , 32 respectively ...

Q:-find the maximum and minimum values of F(x)=sinx+1/2cosx in 0<=x<=∩/2 ...

TMH iit jee for 2008: pg-21.16 , f(x)=sin(2x+1) f:R→[-1,1] domain is restricted to [-3Π/4 - 1/2 , -Π/2-1/2] In this case find onto or not? Can u pls explain with the help of graph? *Image* /hide] I think it is not onto .. ...

** edited ******* ...

y^(1/n)+y^(-1/n)=2x then (x^2-1)y''+x y'=n^2 y proof ...